Question

graph the image of j(7, 8) after a translation 9 units left.

Explanation:

Step1: Recall translation rule for x - coordinate

A translation 9 units left means subtract 9 from the x - coordinate of the point. The point is \(J(7,8)\), and the x - coordinate is \(x = 7\).
The new x - coordinate is \(x'=7 - 9=- 2\).

Step2: Note y - coordinate remains the same

The y - coordinate of a point does not change when translating horizontally. The y - coordinate of point \(J\) is \(y = 8\), and the new y - coordinate \(y'=8\).
So the image of \(J(7,8)\) after a translation 9 units left is \(J'(-2,8)\).
To graph it, find the point \((-2,8)\) on the coordinate - plane. Start at the origin, move 2 units to the left along the x - axis and 8 units up along the y - axis and mark the point.

Answer:

The image of the point \(J(7,8)\) after a translation 9 units left is the point \(J'(-2,8)\).