Question

graph the compound inequality.

x ≥ -16 and x ≤ -12

plot the endpoints. select an endpoint to change it from closed to open. select the a segment, ray, or line to delete it.

Explanation:

Step1: Analyze the inequality \(x\geq - 16\)

For \(x\geq - 16\), we plot a closed circle at \(-16\) (because the inequality includes equality) and draw a ray to the right.

Step2: Analyze the inequality \(x\leq - 12\)

For \(x\leq - 12\), we plot a closed circle at \(-12\) (because the inequality includes equality) and draw a ray to the left.

Step3: Find the intersection (since it is an 'and' compound inequality)

The intersection of \(x\geq - 16\) and \(x\leq - 12\) is the segment between \(-16\) and \(-12\) including both endpoints.

Answer:

Plot a closed circle at \(-16\) and \(-12\) and connect them with a segment.