Question

go step by step to reduce the radical.
\\(\sqrt{160}\\)
\\(\sqrt{16} \cdot \sqrt{10}\\)
\\(\square \sqrt{\square}\\)

Explanation:

Step1: Factor radicand into perfect square

$\sqrt{160} = \sqrt{16 \times 10}$

Step2: Apply product property of radicals

$\sqrt{16 \times 10} = \sqrt{16} \cdot \sqrt{10}$

Step3: Simplify perfect square root

$\sqrt{16} = 4$, so $4 \cdot \sqrt{10}$

Answer:

$4\sqrt{10}$