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given points j(3,5), a(5,4), and g(4,2), graph δjag and its reflection …

Question

given points j(3,5), a(5,4), and g(4,2), graph δjag and its reflection image as indicated. ( r_{y\text{-axis}} ) choose the correct graph below. \\( \bigcirc \\) a. \\( \bigcirc \\) b. \\( \bigcirc \\) c. \\( \bigcirc \\) d.

Explanation:

Step1: Recall Reflection Over y - axis

The rule for reflecting a point \((x,y)\) over the \(y\) - axis is \((x,y)\to(-x,y)\).
For point \(J(3,5)\), after reflection over \(y\) - axis, \(J'\) has coordinates \((- 3,5)\).
For point \(A(5,4)\), after reflection over \(y\) - axis, \(A'\) has coordinates \((-5,4)\).
For point \(G(4,2)\), after reflection over \(y\) - axis, \(G'\) has coordinates \((-4,2)\).

Step2: Analyze the Graphs

We need to check which graph has the original triangle \(\triangle JAG\) with vertices \(J(3,5)\), \(A(5,4)\), \(G(4,2)\) and its reflection \(\triangle J'A'G'\) with vertices \(J'(-3,5)\), \(A'(-5,4)\), \(G'(-4,2)\).
Looking at the coordinates, the original triangle should be on the right - hand side of the \(y\) - axis (since \(x\) - coordinates of \(J\), \(A\), \(G\) are positive) and the reflected triangle should be on the left - hand side of the \(y\) - axis (since \(x\) - coordinates of \(J'\), \(A'\), \(G'\) are negative). Also, the \(y\) - coordinates remain the same.
Now, let's check the coordinates of the vertices in each graph:

  • For the original triangle \(J(3,5)\), \(A(5,4)\), \(G(4,2)\): \(x\) - coordinates are \(3\), \(5\), \(4\) (positive, right of \(y\) - axis), \(y\) - coordinates are \(5\), \(4\), \(2\).
  • For the reflected triangle \(J'(-3,5)\), \(A'(-5,4)\), \(G'(-4,2)\): \(x\) - coordinates are \(-3\), \(-5\), \(-4\) (negative, left of \(y\) - axis), \(y\) - coordinates are \(5\), \(4\), \(2\).

Looking at the graphs, we need to check which graph has the original triangle with \(x\) - coordinates \(3\), \(5\), \(4\) and the reflected triangle with \(x\) - coordinates \(-3\), \(-5\), \(-4\) (and same \(y\) - coordinates). After analyzing the graphs, the correct graph should have the original triangle on the right (with \(J(3,5)\), \(A(5,4)\), \(G(4,2)\)) and the reflected triangle on the left (with \(J'(-3,5)\), \(A'(-5,4)\), \(G'(-4,2)\)). Among the options, the graph that matches this is the one where the blue triangle (reflected) is on the left with vertices at \((-3,5)\), \((-5,4)\), \((-4,2)\) and the black triangle (original) is on the right with vertices at \((3,5)\), \((5,4)\), \((4,2)\). So the correct graph is the one that shows this correct reflection.

Answer:

The correct graph is the one (among A, B, C, D) that has the original triangle with vertices \(J(3,5)\), \(A(5,4)\), \(G(4,2)\) on the right of the \(y\) - axis and the reflected triangle with vertices \(J'(-3,5)\), \(A'(-5,4)\), \(G'(-4,2)\) on the left of the \(y\) - axis. (Based on the reflection rule and coordinate analysis, the correct option is the one that matches the reflection of the points over the \(y\) - axis. If we assume the options are as per the standard reflection, the correct graph is the one where the blue triangle is the reflection (left of \(y\) - axis) and black is original (right of \(y\) - axis) with correct coordinates. For example, if option C is the one with \(J(3,5)\), \(A(5,4)\), \(G(4,2)\) on the right and \(J'(-3,5)\), \(A'(-5,4)\), \(G'(-4,2)\) on the left, then the answer is C. But since the exact visual is needed, but from the rule, the correct graph should follow the reflection over \(y\) - axis rule. )

(Note: Since the user has a set of graphs, the final answer depends on the visual. But the process is to apply the reflection over \(y\) - axis rule \((x,y)\to(-x,y)\) to each vertex and then match with the given graphs. )