QUESTION IMAGE
Question
given the particulate model which depicts the mechanism for the decomposition of \\(\text{no}_2\\), answer the following questions.
step 1:
step 2:
part 1 (1 point)
what is the chemical formula for the intermediate?
part 2 (1 point)
write a balanced equation for the overall chemical reaction. do not add states of matter.
Identify chemical species from the particulate model
Using the Reaction Mechanisms knowledge point
- Red spheres represent oxygen (\(\text{O}\)) atoms and blue spheres represent nitrogen (\(\text{N}\)) atoms.
- Step 1 reactants: One \(\text{NO}\) molecule (one blue, one red) and one \(\text{NO}_2\) molecule (one blue, two red).
- Step 1 transition/products: The model shows a collision forming a temporary association, which then decomposes into \(\text{NO}\) (one blue, one red) and \(\text{NO}_3\) (one blue, three red).
- Step 1 equation:
Simplifying by removing the spectator \(\text{NO}\) molecule that remains unchanged:
Let's re-examine the spheres in Step 1:
- Left: \(\text{NO}\) (blue-red) + \(\text{NO}_2\) (red-blue-red).
- Middle: They collide to form a transient state.
- Right: \(\text{NO}\) (blue-red) + \(\text{NO}_3\) (blue with three red spheres).
- Wait, let's count the atoms on the right of Step 1: one blue-red (\(\text{NO}\)) and one blue-three red (\(\text{NO}_3\)).
- Total atoms on left: 2 blue, 3 red.
- Total atoms on right: 2 blue, 4 red. This is unbalanced.
- Let's look closer at Step 1:
- Reactant 1: \(\text{NO}_2\) (one blue, two red).
- Reactant 2: \(\text{NO}_2\) (one blue, two red).
- Yes, both reactant molecules in Step 1 have one blue sphere and two red spheres. Thus, they are both \(\text{NO}_2\).
- Products of Step 1: One \(\text{NO}\) (one blue, one red) and one \(\text{NO}_3\) (one blue, three red).
- Balanced Step 1 equation:
- Step 2:
- Reactant: \(\text{NO}_3\) (one blue, three red).
- Products: \(\text{NO}\) (one blue, one red) + \(\text{O}_2\) (two red).
- Balanced Step 2 equation:
Determine the chemical formula of the intermediate
Using the Reaction Intermediates knowledge point
- An intermediate is produced in an early step and consumed in a subsequent step.
- \(\text{NO}_3\) is produced in Step 1 and consumed in Step 2.
- Therefore, the intermediate is \(\text{NO}_3\).
Determine the overall balanced chemical equation
Using the Overall Reaction Equations knowledge point
- Sum the elementary steps:
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Question 1
\(\text{NO}_3\)
Question 2
\(2\text{NO}_2
ightarrow 2\text{NO} + \text{O}_2\)