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given: ∠a ≅ ∠c. d is the midpoint of \\(\\overline{ac}\\). \\(\\overlin…

Question

given: ∠a ≅ ∠c. d is the midpoint of \\(\overline{ac}\\). \\(\overline{ac} \perp \overline{bd}\\).
prove: \\(\triangle abc\\) is an isosceles triangle.
diagram of triangle abc with d on ac, bd connecting to b
flowchart and justification boxes:

  • ∠a ≅ ∠c is given.
  • d is the midpoint of \\(\overline{ac}\\) is given.
  • \\(\overline{ac} \perp \overline{bd}\\) is given.
  • \\(\triangle abd ≅ \triangle cbd\\) by asa
  • justifications: \\(\overline{ad} ≅ \overline{cd}\\) by definition of a midpoint; \\(\angle bda ≅ \angle bdc\\) because all right angles are congruent; \\(\angle abd ≅ \angle cbd\\) ?; \\(\overline{ab} ≅ \overline{cb}\\) by cpctc or definition of midpoint?
  • \\(\triangle abc\\) is an isosceles triangle

Explanation:

Step1: Identify Midpoint Side

D is the midpoint of \( \overline{AC} \), so \( \overline{AD} \cong \overline{CD} \) (by definition of a midpoint).

Step2: Identify Right Angles

\( \overline{AC} \perp \overline{BD} \), so \( \angle BDA \cong \angle BDC \) (all right angles are congruent).

Step3: Identify Given Angle

\( \angle A \cong \angle C \) (given).

Step4: Prove Triangle Congruence

Using ASA (Angle-Side-Angle) criterion: \( \angle A \cong \angle C \), \( \overline{AD} \cong \overline{CD} \), \( \angle BDA \cong \angle BDC \), so \( \triangle ABD \cong \triangle CBD \).

Step5: Use CPCTC

By CPCTC (Corresponding Parts of Congruent Triangles are Congruent), \( \overline{AB} \cong \overline{CB} \).

Step6: Conclude Isosceles Triangle

A triangle with two congruent sides (\( \overline{AB} \cong \overline{CB} \)) is isosceles, so \( \triangle ABC \) is isosceles.

Answer:

The proof shows \( \triangle ABC \) is isosceles by proving \( \overline{AB} \cong \overline{CB} \) via ASA congruence of \( \triangle ABD \) and \( \triangle CBD \), using midpoint, right angles, and given angle congruence.