QUESTION IMAGE
Question
given the following names, write the formulas
- calcium carbonate
- sodium cyanide
- potassium nitrate
- aluminum chlorate
- barium chromate
- calcium hydroxide
- potassium nitrite
- lithium carbonate
- magnesium acetate
- aluminum sulfate
- potassium iodide
- barium chloride
- lithium bromide
- sodium hypochlorite
- iron (iii) sulfate
- tin (iv) oxide
- copper (ii) iodide
- strontium chloride
- lithium acetate
- magnesium hydroxide
Step1: Analyze Calcium carbonate
Calcium (Ca) has a charge of +2, carbonate ($\text{CO}_3^{2 - }$) has a charge of -2. To balance charges, the formula is $\text{CaCO}_3$.
Step2: Analyze Sodium cyanide
Sodium (Na) has +1 charge, cyanide ($\text{CN}^ - $) has -1 charge. Formula: $\text{NaCN}$.
Step3: Analyze Potassium nitrate
Potassium (K) +1, nitrate ($\text{NO}_3^ - $) -1. Formula: $\text{KNO}_3$.
Step4: Analyze Aluminum chlorate
Aluminum (Al) +3, chlorate ($\text{ClO}_3^ - $) -1. Need 3 chlorate ions. Formula: $\text{Al(ClO}_3\text{)}_3$.
Step5: Analyze Barium chromate
Barium (Ba) +2, chromate ($\text{CrO}_4^{2 - }$) -2. Formula: $\text{BaCrO}_4$.
Step6: Analyze Calcium hydroxide
Calcium (Ca) +2, hydroxide ($\text{OH}^ - $) -1. Need 2 hydroxide ions. Formula: $\text{Ca(OH)}_2$.
Step7: Analyze Potassium nitrite
Potassium (K) +1, nitrite ($\text{NO}_2^ - $) -1. Formula: $\text{KNO}_2$.
Step8: Analyze Lithium carbonate
Lithium (Li) +1, carbonate ($\text{CO}_3^{2 - }$) -2. Need 2 Li ions. Formula: $\text{Li}_2\text{CO}_3$.
Step9: Analyze Magnesium acetate
Magnesium (Mg) +2, acetate ($\text{C}_2\text{H}_3\text{O}_2^ - $) -1. Need 2 acetate ions. Formula: $\text{Mg(C}_2\text{H}_3\text{O}_2\text{)}_2$.
Step10: Analyze Aluminum sulfate
Aluminum (Al) +3, sulfate ($\text{SO}_4^{2 - }$) -2. Find LCM of 3 and 2 (6). So 2 Al and 3 sulfate. Formula: $\text{Al}_2(\text{SO}_4)_3$.
Step11: Analyze Potassium iodide
Potassium (K) +1, iodide (I⁻) -1. Formula: $\text{KI}$.
Step12: Analyze Barium chloride
Barium (Ba) +2, chloride (Cl⁻) -1. Need 2 Cl⁻. Formula: $\text{BaCl}_2$.
Step13: Analyze Lithium bromide
Lithium (Li) +1, bromide (Br⁻) -1. Formula: $\text{LiBr}$.
Step14: Analyze Sodium hypochlorite
Sodium (Na) +1, hypochlorite ($\text{ClO}^ - $) -1. Formula: $\text{NaClO}$.
Step15: Analyze Iron (III) sulfate
Iron (III) (Fe³⁺), sulfate ($\text{SO}_4^{2 - }$). LCM of 3 and 2 is 6. 2 Fe and 3 sulfate. Formula: $\text{Fe}_2(\text{SO}_4)_3$.
Step16: Analyze Tin (IV) oxide
Tin (IV) (Sn⁴⁺), oxide (O²⁻). LCM of 4 and 2 is 4. 1 Sn and 2 O. Formula: $\text{SnO}_2$.
Step17: Analyze Copper (II) iodide
Copper (II) (Cu²⁺), iodide (I⁻). Need 2 I⁻. Formula: $\text{CuI}_2$.
Step18: Analyze Strontium chloride
Strontium (Sr) +2, chloride (Cl⁻) -1. Need 2 Cl⁻. Formula: $\text{SrCl}_2$.
Step19: Analyze Lithium acetate
Lithium (Li) +1, acetate ($\text{C}_2\text{H}_3\text{O}_2^ - $) -1. Formula: $\text{LiC}_2\text{H}_3\text{O}_2$.
Step20: Analyze Magnesium hydroxide
Magnesium (Mg) +2, hydroxide ($\text{OH}^ - $) -1. Need 2 OH⁻. Formula: $\text{Mg(OH)}_2$.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- $\boldsymbol{\text{CaCO}_3}$
- $\boldsymbol{\text{NaCN}}$
- $\boldsymbol{\text{KNO}_3}$
- $\boldsymbol{\text{Al(ClO}_3\text{)}_3}$
- $\boldsymbol{\text{BaCrO}_4}$
- $\boldsymbol{\text{Ca(OH)}_2}$
- $\boldsymbol{\text{KNO}_2}$
- $\boldsymbol{\text{Li}_2\text{CO}_3}$
- $\boldsymbol{\text{Mg(C}_2\text{H}_3\text{O}_2\text{)}_2}$
- $\boldsymbol{\text{Al}_2(\text{SO}_4)_3}$
- $\boldsymbol{\text{KI}}$
- $\boldsymbol{\text{BaCl}_2}$
- $\boldsymbol{\text{LiBr}}$
- $\boldsymbol{\text{NaClO}}$
- $\boldsymbol{\text{Fe}_2(\text{SO}_4)_3}$
- $\boldsymbol{\text{SnO}_2}$
- $\boldsymbol{\text{CuI}_2}$
- $\boldsymbol{\text{SrCl}_2}$
- $\boldsymbol{\text{LiC}_2\text{H}_3\text{O}_2}$
- $\boldsymbol{\text{Mg(OH)}_2}$