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Question
given the following function, find f(-1), f(0), and f(3).
f(x) = x² - 1
f(-1) = \square
Step1: Substitute \( x = -1 \) into \( f(x) \)
To find \( f(-1) \), we substitute \( x = -1 \) into the function \( f(x) = x^2 - 1 \). So we have \( f(-1)=(-1)^2 - 1 \).
Step2: Calculate the value
First, calculate \( (-1)^2 \), which is equal to \( 1 \). Then subtract \( 1 \) from it: \( 1 - 1 = 0 \).
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