Question

given the following function, find f(-1), f(0), and f(3).
f(x) = x² - 1
f(-1) = 0
f(0) = □

Explanation:

Step1: Substitute x = 0 into the function

We have the function \( f(x) = x^2 - 1 \). To find \( f(0) \), we replace \( x \) with \( 0 \) in the function.

Step2: Calculate the value

\( f(0) = 0^2 - 1 \)
First, calculate \( 0^2 \), which is \( 0 \). Then subtract \( 1 \) from \( 0 \): \( 0 - 1 = -1 \).

Step1: Substitute x = 3 into the function

Using the function \( f(x) = x^2 - 1 \), replace \( x \) with \( 3 \).

Step2: Calculate the value

\( f(3) = 3^2 - 1 \)
First, calculate \( 3^2 = 9 \). Then subtract \( 1 \) from \( 9 \): \( 9 - 1 = 8 \).

Answer:

\( f(0) = -1 \)

For completeness, let's also find \( f(3) \):