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given $m \\parallel n$, find the value of x. (5x+23)° on line m, (6x-4)…

Question

given $m \parallel n$, find the value of x.

(5x+23)° on line m, (6x-4)° on line n, cut by transversal t.

answer attempt 1 out of 2

$x = \square$

Explanation:

Step1: Identify Angle Relationship

Since \( m \parallel n \), the two angles \( (5x + 23)^\circ \) and \( (6x - 4)^\circ \) are alternate exterior angles, so they are equal. Thus, we set up the equation:
\( 5x + 23 = 6x - 4 \)

Step2: Solve for \( x \)

Subtract \( 5x \) from both sides:
\( 23 = x - 4 \)

Add 4 to both sides:
\( x = 23 + 4 = 27 \)

Answer:

\( x = 27 \)