Question

1. given $f(x) = x^3 + 3x^2 - 5$

evaluate when $x = -7$

Explanation:

Step1: Substitute \( x = -7 \) into the function \( f(x) = x^3 + 3x^2 - 5 \)

We get \( f(-7) = (-7)^3 + 3\times(-7)^2 - 5 \)

Step2: Calculate each term

First, calculate \( (-7)^3 \): \( (-7)^3 = -343 \)
Then, calculate \( 3\times(-7)^2 \): \( (-7)^2 = 49 \), so \( 3\times49 = 147 \)

Step3: Combine the terms

\( f(-7) = -343 + 147 - 5 \)
First, \( -343 + 147 = -196 \)
Then, \( -196 - 5 = -201 \)

Answer:

\( -201 \)