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geometry volume of a cylinder the radius of a cylindrical construction …

Question

geometry
volume of a cylinder
the radius of a cylindrical construction pipe is 2 ft. if the pipe is 22 ft long, what is its volume?
use the value 3.14 for π, and round your answer to the nearest whole number.
be sure to include the correct unit in your answer.
(there is an image of a cylinder with radius 2 ft and length 22 ft, along with a input box and unit options ft, ft², ft³)

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume \( V \) of a cylinder is \( V=\pi r^{2}h \), where \( r \) is the radius and \( h \) is the height (or length, in this case) of the cylinder.

Step2: Identify the given values

We are given that the radius \( r = 2\) ft and the length (height) \( h=22\) ft, and we use \( \pi = 3.14\).

Step3: Substitute the values into the formula

First, calculate \( r^{2}\): \( r^{2}=(2)^{2}=4\) square feet.
Then, multiply by \( \pi \) and \( h \): \( V = 3.14\times4\times22\).
First, calculate \( 3.14\times4 = 12.56\).
Then, calculate \( 12.56\times22\). \( 12.56\times22 = 276.32\).

Step4: Round to the nearest whole number

Rounding \( 276.32\) to the nearest whole number gives \( 276\). The unit for volume of a cylinder is cubic feet (\( \text{ft}^3\)).

Answer:

\( 276 \text{ ft}^3 \)