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Question
geometry unit 4 test
- in the diagram below, \\( \overline{rs} \\) and \\( \overline{rt} \\) intersect \\( \overline{de} \\) at points t and s.
which of these statements is true about \\( \triangle rst \\)?
a \\( \triangle rst \\) is an isosceles triangle
b. \\( \triangle rst \\) is a scalene triangle
c. \\( \triangle rst \\) is a right triangle
d. \\( \triangle rst \\) is an equilateral triangle
- given: \\( \triangle abc \\) with \\( m\angle a=(7x)^{circ} \\), \\( m\angle b=(6x)^{circ} \\), and \\( m\angle c=(2x)^{circ} \\). find the \\( m\angle a \\).
a. \\( m\angle a = 15^{circ} \\)
b. \\( m\angle a = 24^{circ} \\)
c. \\( m\angle a = 72^{circ} \\)
d. \\( m\angle a = 84^{circ} \\)
- given the following triangle, what is the value of x?
Step1: Find the angles of \(\triangle RST\)
We know that the sum of angles on a straight - line is \(180^{\circ}\).
For \(\angle RTS\), since \(\angle DTR = 130^{\circ}\), then \(\angle RTS=180 - 130=50^{\circ}\) (linear - pair of angles).
For \(\angle RST\), since \(\angle ESR = 130^{\circ}\), then \(\angle RST = 180 - 130=50^{\circ}\) (linear - pair of angles).
Step2: Use the angle - sum property of a triangle
In \(\triangle RST\), by the angle - sum property of a triangle (\(\angle R+\angle RTS+\angle RST = 180^{\circ}\)). Let \(\angle R=x\). Then \(x + 50+50=180\).
Since \(\angle RTS=\angle RST = 50^{\circ}\), two angles of \(\triangle RST\) are equal.
Step3: Solve for \(x\) in \(\triangle ABC\)
By the angle - sum property of a triangle (\(\angle A+\angle B+\angle C=180^{\circ}\)).
Given \(\angle A=(7x)^{\circ}\), \(\angle B=(6x)^{\circ}\), \(\angle C=(2x)^{\circ}\).
Then \(\angle A=7x\). Substitute \(x = 12\) into \(\angle A\), \(\angle A=7\times12 = 84^{\circ}\)
Step4: Solve for \(x\) in the equilateral triangle
Since the triangle is equilateral (all angles are equal), each angle is \(60^{\circ}\).
If one angle is \((4x + 8)^{\circ}\), then \(4x+8=60\)
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- A. \(\triangle RST\) is an isosceles triangle
- D. \(m\angle A = 84^{\circ}\)
- \(x = 13\)