Question

a gas sample has an initial pressure of 1.18 atm and occupies a volume of 2.0 l. if the pressure is reduced to 0.75 atm while keeping the temperature constant, what will be the new volume of the gas? the new volume is 3.14 select one select one atm kpa l ml moles k c

Explanation:

Step1: <Apply Boyle's Law>

Boyle's Law is \(P_1V_1 = P_2V_2\) (where \(P_1\) and \(V_1\) are initial pressure and volume, \(P_2\) and \(V_2\) are final pressure and volume).
Given \(P_1=1.18\) atm, \(V_1 = 2.0\) L, \(P_2=0.75\) atm.
We need to solve for \(V_2\), so \(V_2=\frac{P_1V_1}{P_2}\).

Step2: <Substitute values>

Substitute the values into the formula: \(V_2=\frac{1.18\times2.0}{0.75}\).
First, calculate \(1.18\times2.0 = 2.36\).
Then, \(V_2=\frac{2.36}{0.75}\approx3.15\) L.

Answer:

\(3.15\) L