Question

a gas occupies a volume of 6.0 l at a pressure of 2.0 atm. if the gas is compressed to a volume of 3,000 ml, what will be the new pressure of the gas, assuming the temperature remains constant? a.004 atm b 4 atm c 9.0 atm d 9,000 atm

Explanation:

Step1: Convert volume units

We know that \(1L = 1000mL\), so \(V_1=6.0L\) and \(V_2 = 3000mL=3.0L\).

Step2: Apply Boyle's law

Boyle's law is \(P_1V_1 = P_2V_2\). Given \(P_1 = 2.0atm\), \(V_1 = 6.0L\), \(V_2=3.0L\). We can solve for \(P_2\) by the formula \(P_2=\frac{P_1V_1}{V_2}\).
Substitute the values: \(P_2=\frac{2.0atm\times6.0L}{3.0L}\).
First, calculate \(2.0\times6.0 = 12.0\), then \(\frac{12.0}{3.0}=4.0\).

Answer:

B. 4 atm