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Question
in a game of tug of war, team one pulls to the right with a force of 500 newtons and team two pulls to the left with a force of 600 newtons. what is the net force? click the best answer and drag it into the white box.
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100 n to the right
0 n; balanced
1100 n to the left
100 n to the left
note: use ctrl+d to drag the option via keyboard
Step1: Define forces direction
Let right - direction force be positive, so team one's force \( F_1 = 500\space N \) (to the right), team two's force \( F_2=- 600\space N \) (to the left, negative sign for opposite direction).
Step2: Calculate net force
Net force \( F_{net}=F_1 + F_2=500+( - 600)=- 100\space N \). The negative sign indicates the net force is to the left with a magnitude of \( 100\space N \).
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100 N to the left