Question

1 gabriel kicks a soccer ball with an initial velocity 22 meters per second, at an angle of 16° above the ground what is the vertical component of the initial velocity? 6.1 m/s -21 m/s -6.1 m/s 21 m/s

Explanation:

Step1: Recall the formula for vertical component of velocity

The vertical component of velocity \(v_y\) is given by \(v_y = v\sin\theta\), where \(v\) is the initial velocity and \(\theta\) is the angle of projection.

Step2: Substitute the given values

Here, \(v = 22\space m/s\) and \(\theta=16^{\circ}\). So, \(v_y=22\times\sin(16^{\circ})\).
We know that \(\sin(16^{\circ})\approx0.2756\). Then \(v_y = 22\times0.2756 = 6.0632\approx6.1\space m/s\).

Answer:

6.1 m/s