Question

function a and function b are linear functions.
function a
$y = 4x - 2$
function b
graph of function b on a coordinate plane
which statement is true?
the $y$-value of function a when $x = 1$ is greater than the $y$-value of function b when $x = 1$.
the $y$-value of function a when $x = 1$ is less than the $y$-value of function b when $x = 1$.

Explanation:

Step1: Calculate y-value of Function A at x=1

Substitute x=1 into Function A: $y = 4(1) - 2 = 2$.

Step2: Find y-value of Function B at x=1

From the graph, Function B passes through (0,-6) and (1,-2) (slope = 4, so y increases by 4 when x increases by 1). At x=1, y=-2.

Step3: Compare the two y-values

Function A's y-value (2) > Function B's y-value (-2).

Answer:

The y-value of Function A when x = 1 is greater than the y-value of Function B when x = 1.