Question

function 1:
function 2:

x	1	2	3	4	5
p(x)	0	3	13	16	19

Explanation:

Step1: Find slope of Function 1 (q(x))

From the graph, q(x) passes through (0, 9) and (3, 0). Slope $m = \frac{0 - 9}{3 - 0} = -3$. So equation: $q(x) = -3x + 9$.

Step2: Analyze Function 2 (p(x))

Check differences: $3 - 0 = 3$, $13 - 3 = 10$, $16 - 13 = 3$, $19 - 16 = 3$. Not linear (since differences aren't constant). But let's evaluate at x=3: q(3) = -3(3)+9 = 0; p(3)=13. Wait, maybe find at x=1: q(1)= -3(1)+9=6; p(1)=0. x=2: q(2)= -3(2)+9=3; p(2)=3. Oh! At x=2, q(2)=3 and p(2)=3. So they intersect at x=2.

Answer:

The functions intersect at x = 2 (or the point (2, 3))