Question

1. four liquids with the following densities are poured into a beaker. liquid a: 0.85 g/ml liquid b: 2.50 g/ml liquid c: water liquid d: 1.8 g/ml

a. label each liquid layer with the correct letter.
b. an object with a mass of 12.75g and a volume of 9.83 cm³ is place into the beaker. draw the object where you would expect to find it in the beaker and label it with its density.

Explanation:

Step1: Recall water density

The density of water (Liquid C) is 1 g/mL.

Step2: Compare densities

Arrange the densities in ascending - order: Liquid A (0.85 g/mL) < Liquid C (1 g/mL) < Liquid D (1.8 g/mL) < Liquid B (2.50 g/mL). The least - dense liquid will be on the top and the most - dense liquid will be at the bottom. So, from top to bottom, the layers are A, C, D, B.

Step3: Calculate object density

Use the density formula $
ho=\frac{m}{V}$, where $m = 12.75g$ and $V=9.83cm^{3}$. Then $
ho=\frac{12.75}{9.83}\approx1.3g/cm^{3}$ (since $1cm^{3}=1mL$).

Step4: Determine object position

Since $1g/mL<1.3g/mL < 1.8g/mL$, the object will be between Liquid C and Liquid D.

Answer:

a. From top to bottom: A, C, D, B
b. The density of the object is approximately 1.3 g/mL. It will be between Liquid C and Liquid D.