Question

formation of water reaction
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Explanation:

Step1: Analyze the reactants and products

We have \(2H_2\) (hydrogen gas) and \(O_2\) (oxygen gas) as reactants, and \(2H_2O\) (water) as the product.

Step2: Count the atoms

• For hydrogen (\(H\)): In \(2H_2\), there are \(2\times2 = 4\) \(H\) atoms. In \(2H_2O\), there are \(2\times2=4\) \(H\) atoms.
• For oxygen (\(O\)): In \(O_2\), there are \(2\) \(O\) atoms. In \(2H_2O\), there are \(2\times1 = 2\) \(O\) atoms.

Answer:

The chemical equation \(2H_2+O_2
ightarrow2H_2O\) is balanced as the number of hydrogen and oxygen atoms is the same on both sides of the equation.