Question

formation of ionic compounds

1. how do you determine the charges on the ions in an ionic compound?

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Explanation:

To determine the charges on ions in an ionic compound, one can refer to the periodic table. Metals (usually on the left side) tend to lose electrons and form cations. For example, group 1 metals lose 1 electron to form \(+1\) cations, group 2 metals lose 2 electrons to form \(+2\) cations. Non - metals (usually on the right side) tend to gain electrons and form anions. Group 17 elements (halogens) gain 1 electron to form \(- 1\) anions, group 16 elements gain 2 electrons to form \(-2\) anions. Also, for polyatomic ions, their charges are known values (e.g., sulfate \(\text{SO}_{4}^{2 -}\) has a charge of \(-2\)). Another way is to use the principle of electrical neutrality of the ionic compound. If the formula of the ionic compound is known (e.g., \(\text{NaCl}\)), and the charge of one ion is known (sodium in group 1 has a \(+1\) charge), then the charge of the other ion (chloride) can be found. Since the compound is neutral (\(+1 + x=0\), so \(x=-1\) for chloride).

Answer:

The charges on ions in an ionic compound can be determined by referring to the element's position in the periodic table (for mono - atomic ions, based on group - related electron - loss/gain tendencies) and using the principle of electrical neutrality of the compound (if the formula is known). For polyatomic ions, their standard charges (from chemical knowledge) are used.