Question

the following simple function has an optional parameter. (note: default value for delimiter is a string of length 1.)
def join(word1, word2, delimiter= ):
joined = str(word1) + str(delimiter) + str(word2)
return joined
what does the function return if we call it as follows:
join(1, \world\)

Explanation:

Step1: Substitute parameters

Substitute word1 = 1, word2 = "world", and delimiter = ' ' (default value) into the function.

$$\begin{align*} joined&=\text{str}(1)+\text{str(' ')}+\text{str("world")}\\ \end{align*}$$

Step2: Convert to strings and concatenate

Convert each parameter to a string. str(1) is "1", str(' ') is " ", and str("world") is "world". Then concatenate them:

$$\begin{align*} joined&="1"+" "+"world"\\ &="1 world" \end{align*}$$

Answer:

"1 world"