Question

for the following exercise, evaluate the function f at the given values.
$f(x) = 3x^2 - 5x + 5$
$f(-2) = $
$f(-1) = $
$f(0) = $
$f(1) = $
$f(2) = $
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Explanation:

Step1: Evaluate \( f(-2) \)

Substitute \( x = -2 \) into \( f(x) = 3x^2 - 5x + 5 \):
\( f(-2) = 3(-2)^2 - 5(-2) + 5 = 3(4) + 10 + 5 = 12 + 10 + 5 = 27 \)

Step2: Evaluate \( f(-1) \)

Substitute \( x = -1 \) into \( f(x) \):
\( f(-1) = 3(-1)^2 - 5(-1) + 5 = 3(1) + 5 + 5 = 3 + 5 + 5 = 13 \)

Step3: Evaluate \( f(0) \)

Substitute \( x = 0 \) into \( f(x) \):
\( f(0) = 3(0)^2 - 5(0) + 5 = 0 - 0 + 5 = 5 \)

Step4: Evaluate \( f(1) \)

Substitute \( x = 1 \) into \( f(x) \):
\( f(1) = 3(1)^2 - 5(1) + 5 = 3 - 5 + 5 = 3 \)

Step5: Evaluate \( f(2) \)

Substitute \( x = 2 \) into \( f(x) \):
\( f(2) = 3(2)^2 - 5(2) + 5 = 3(4) - 10 + 5 = 12 - 10 + 5 = 7 \)

Answer:

\( f(-2) = 27 \), \( f(-1) = 13 \), \( f(0) = 5 \), \( f(1) = 3 \), \( f(2) = 7 \)