Question

c. for the following electron configurations determine the possible elements they may

1. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³:
2. xe 6s²4f¹⁴5d¹⁰6p²:

Explanation:

Step1: Count electrons for first configuration

The electron - configuration $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{3}$:
The number of electrons is $2 + 2+6 + 2+6 + 2+10 + 3=33$.
The element with 33 electrons is Arsenic (As) since the atomic number (number of protons = number of electrons in a neutral atom) is 33.

Step2: Count electrons for second configuration

The electron - configuration $[Xe]6s^{2}4f^{14}5d^{10}6p^{2}$:
Xenon ($Xe$) has 54 electrons. Adding the extra electrons: $2 + 14+10 + 2=28$.
The total number of electrons is $54 + 28 = 82$.
The element with 82 electrons is Lead (Pb).

Answer:

1. Arsenic (As)
2. Lead (Pb)