Question

a flashlight has a resistance of 2.4 ω. what voltage is applied by the batteries if the current in the circuit is 2.5 a?
○ 0.96 v
○ 1.0 v
○ 4.9 v
○ 6.0 v

Explanation:

Step1: Recall Ohm's Law

Ohm's Law states that \( V = I \times R \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance.

Step2: Substitute values into the formula

Given \( R = 2.4\ \Omega \) and \( I = 2.5\ A \), substitute into \( V = I \times R \).
\( V = 2.5\ A \times 2.4\ \Omega \)

Step3: Calculate the product

\( 2.5 \times 2.4 = 6.0 \), so \( V = 6.0\ V \).

Answer:

6.0 V (corresponding to the option "6.0 V")