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find the x- and y-intercepts 32. 6x - 3y = 12

Question

find the x- and y-intercepts

  1. 6x - 3y = 12

Explanation:

Step1: Find x-intercept (set y=0)

Set \( y = 0 \) in \( 6x - 3y = 12 \).
Equation becomes \( 6x - 3(0) = 12 \), so \( 6x = 12 \).
Divide both sides by 6: \( x = \frac{12}{6} = 2 \).

Step2: Find y-intercept (set x=0)

Set \( x = 0 \) in \( 6x - 3y = 12 \).
Equation becomes \( 6(0) - 3y = 12 \), so \( -3y = 12 \).
Divide both sides by -3: \( y = \frac{12}{-3} = -4 \).

Answer:

x-intercept: \( 2 \) (or \( (2, 0) \)), y-intercept: \( -4 \) (or \( (0, -4) \))