Question

find the volume of a cone with a base radius of 6 ft and a height of 9 ft.
use the value 3.14 for π, and do not do any rounding.
be sure to include the correct unit in your answer.

Explanation:

Step1: Escribir la fórmula del volumen del cono

$$V=\frac{1}{3}\pi r^{2}h$$

Step2: Sustituir los valores dados ($r = 6$, $h = 9$, $\pi=3.14$) en la fórmula

$$V=\frac{1}{3}\times3.14\times6^{2}\times9$$

Step3: Calcular $6^{2}$

$$6^{2}=36$$

Step4: Sustituir $6^{2}=36$ en la expresión

$$V=\frac{1}{3}\times3.14\times36\times9$$

Step5: Calcular $\frac{1}{3}\times36$

$$\frac{1}{3}\times36 = 12$$

Step6: Sustituir $\frac{1}{3}\times36 = 12$ en la expresión

$$V=12\times3.14\times9$$

Step7: Calcular $12\times9$

$$12\times9 = 108$$

Step8: Sustituir $12\times9 = 108$ en la expresión

$$V=108\times3.14$$

Step9: Calcular $108\times3.14$

$$108\times3.14=(100 + 8)\times3.14=100\times3.14+8\times3.14=314+25.12 = 339.12$$

Answer:

$339.12\ \text{ft}^{3}$