Question

find the value of c and yz if y is between x and z.
xy = 11, yz = 4c, xz = 83
c =
yz =

Explanation:

Step1: Use segment addition postulate

Since \(Y\) is between \(X\) and \(Z\), \(XY + YZ=XZ\).
Substitute the given values: \(11 + 4c=83\).

Step2: Solve for \(c\)

Subtract \(11\) from both sides: \(4c=83 - 11\), so \(4c = 72\).
Divide both sides by \(4\): \(c=\frac{72}{4}=18\).

Step3: Find \(YZ\)

Substitute \(c = 18\) into \(YZ = 4c\). Then \(YZ=4\times18 = 72\).

Answer:

\(c = 18\); \(YZ=72\)