QUESTION IMAGE
Question
find the value of x, y, and z in the parallelogram below.
(3x-6)°
111°
(8y-1)°
(-4z-3)°
answer attempt 1 out of 2
x =
y =
z =
Step1: Find x using opposite angles in parallelogram
In a parallelogram, opposite angles are equal. So, \(3x - 6 = 111\)
\(3x = 111 + 6\)
\(3x = 117\)
\(x = \frac{117}{3}\)
\(x = 39\)
Step2: Find y using consecutive angles in parallelogram
Consecutive angles in a parallelogram are supplementary (sum to \(180^\circ\)). So, \(8y - 1 + 111 = 180\)
\(8y + 110 = 180\)
\(8y = 180 - 110\)
\(8y = 70\)
\(y = \frac{70}{8} = 8.75\) (Wait, correction: Wait, actually, the angle \(8y - 1\) should be equal to the angle opposite to it? Wait no, in the parallelogram, let's recheck. Wait the angles: the angle \(3x - 6\) and \(111^\circ\) are opposite? Wait no, looking at the diagram, the angles: let's see, the angle \(3x - 6\) and \(-4z - 3\) – no, wait, in a parallelogram, opposite angles are equal, and consecutive angles are supplementary. Wait the angle \(111^\circ\) and \(8y - 1\): are they consecutive? Wait no, let's re-express. Wait the angle \(3x - 6\) and \(111^\circ\) – maybe \(3x - 6\) is opposite to \(111^\circ\), so \(3x - 6 = 111\) (correct as step1). Then the angle \(8y - 1\) and \(-4z - 3\) – wait, no, consecutive angles: \(111^\circ\) and \(8y - 1\) should be supplementary? Wait no, maybe I made a mistake. Wait, in a parallelogram, opposite angles are equal, so angle \(A =\) angle \(C\), angle \(B =\) angle \(D\). Also, angle \(A +\) angle \(B = 180^\circ\). So let's label the parallelogram: let's say the top angle is \(3x - 6\), right angle is \(111^\circ\), bottom angle is \(-4z - 3\), left angle is \(8y - 1\). So top and bottom are opposite, right and left are opposite? Wait no, top and bottom: no, in a parallelogram, opposite angles are (top, bottom) and (left, right). Wait, no, adjacent angles are consecutive. So top angle (\(3x - 6\)) and right angle (\(111^\circ\)) are consecutive, so they should be supplementary? Wait no, that can't be, because \(3x - 6 + 111 = 180\) would give \(3x = 75\), \(x = 25\), but that contradicts. Wait, maybe the angle \(3x - 6\) is opposite to \(-4z - 3\), and \(111^\circ\) is opposite to \(8y - 1\). Wait, that makes sense. So opposite angles: \(3x - 6 = -4z - 3\) (no, that might not be). Wait, no, let's check the sum of angles in a parallelogram: sum of all angles is \(360^\circ\), and opposite angles are equal. So let's denote:
Let angle 1: \(3x - 6\)
Angle 2: \(111^\circ\)
Angle 3: \(-4z - 3\)
Angle 4: \(8y - 1\)
So angle 1 = angle 3, angle 2 = angle 4.
Also, angle 1 + angle 2 + angle 3 + angle 4 = 360
Since angle 1 = angle 3, angle 2 = angle 4, so 2(angle 1) + 2(angle 2) = 360 => angle 1 + angle 2 = 180
So angle 1 + angle 2 = 180 => \(3x - 6 + 111 = 180\)
Wait, that's the correct approach. So \(3x - 6 + 111 = 180\)
\(3x + 105 = 180\)
\(3x = 75\)
\(x = 25\) (Oh! I made a mistake earlier. So step1 correction: \(3x - 6 + 111 = 180\) (consecutive angles are supplementary))
So step1 corrected:
Step1: Find x (consecutive angles supplementary)
\(3x - 6 + 111 = 180\)
\(3x + 105 = 180\)
\(3x = 75\)
\(x = 25\)
Step2: Find y (opposite angles equal)
Since angle 2 (111°) and angle 4 (8y - 1) are opposite, so \(8y - 1 = 111\)
\(8y = 112\)
\(y = 14\)
Step3: Find z (opposite angles equal, angle 1 and angle 3)
Angle 1: \(3x - 6 = 3*25 - 6 = 75 - 6 = 69°\)
Angle 3: \(-4z - 3\), so \( -4z - 3 = 69\)
\(-4z = 72\)
\(z = -18\)
Wait, let's verify:
Angle 1: 69°, Angle 2: 111°, Angle 3: 69°, Angle 4: 111°
Sum: 69 + 111 + 69 + 111 = 360°, which is correct.
So correcting step1: I initially thought opposite angles, but actually, consecutive angles are supplementary, so \(3x - 6\)…
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\(x = 25\), \(y = 14\), \(z = -18\)