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find the value of x that makes quadrilateral defg a parallelogram.

Question

find the value of x that makes quadrilateral defg a parallelogram.

Explanation:

Step1: Sumar los ángulos internos

La suma de los ángulos internos de un paralelogramo es \(360^{\circ}\).
\((14x + 96)+(4x + 48)+(12x + 100)+(x + 54)=360\)

Step2: Simplificar la ecuación

Combinar términos semejantes:
\(14x+4x + 12x+x+96 + 48+100+54 = 360\)
\(31x+298 = 360\)

Step3: Resolver para \(x\)

Restar \(298\) de ambos lados:
\(31x=360 - 298\)
\(31x=62\)
Dividir por \(31\):
\(x=\frac{62}{31}\)
\(x = 2\)

Answer:

\(2\)