Question

3 find the value
$(7x + 27)^{circ }$
$(10x - 6)^{circ }$
$(9y - 5)^{circ }$
9
10
11
12
13

Explanation:

Step1: Set up equation for vertical angles

Vertical angles are equal. So \(7x + 27=10x - 6\).

Step2: Solve for \(x\)

Subtract \(7x\) from both sides: \(27 = 3x-6\).
Add \(6\) to both sides: \(33=3x\).
Divide both sides by \(3\): \(x = 11\).

Answer:

\(11\)