Question

find the solution of the system of equations.\

$$\begin{cases}x + y = 8\\\\2x + y = 13\\end{cases}$$

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show your work here\
x =\
y =\
check

Explanation:

Step1: Subtract the first equation from the second

We have the system:

$$\begin{cases} x + y = 8 \\ 2x + y = 13 \end{cases}$$

Subtract the first equation from the second: $(2x + y) - (x + y) = 13 - 8$.
Simplify: $2x + y - x - y = 5$, so $x = 5$.

Step2: Substitute x = 5 into the first equation

Substitute $x = 5$ into $x + y = 8$: $5 + y = 8$.
Solve for $y$: $y = 8 - 5 = 3$.

Answer:

$x = 5$, $y = 3$