Question

find sec θ. (2√21, -4) sec θ = ?√ /

Explanation:

Step1: Calculate the value of \( r \)

Use the formula \( r=\sqrt{x^{2}+y^{2}} \), where \( x = 2\sqrt{21} \) and \( y=-4 \).

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Step2: Calculate \( \sec\theta \)

Recall the formula \( \sec\theta=\frac{r}{x} \).

$$ \sec\theta=\frac{10}{2\sqrt{21}}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21} $$

Answer:

\(\frac{5\sqrt{21}}{21}\)