Question

find the roots of the factored polynomial.
$(x + 3)^3$
write your answer as a list of values separated by commas.
$x = \boxed{}$

Explanation:

Step1: Set the polynomial to zero

To find the roots, we set the factored polynomial equal to zero: \((x + 3)^3 = 0\)

Step2: Solve for x

Taking the cube root of both sides, we get \(x + 3 = \sqrt[3]{0}\). Since \(\sqrt[3]{0}=0\), we have \(x+3 = 0\). Subtracting 3 from both sides gives \(x=-3\). The root \(-3\) has a multiplicity of 3, but we list it once (or as per the question's request for a list of values, we can note the multiplicity but since it's a repeated root, the root is \(-3\)).

Answer:

\(-3\)