Question

find the period in degrees of $f(x)=\frac{1}{2}sin(3x)$
120 degrees
180 degrees
1080 degrees
720 degrees

Explanation:

Step1: Recall the formula for the period of a sine function

The general form of a sine function is \(y = A\sin(Bx + C)+D\), and its period \(T\) (in degrees) is given by \(T=\frac{360^{\circ}}{|B|}\).

Step2: Identify the value of \(B\)

For the function \(f(x)=\frac{1}{2}\sin(3x)\), we have \(B = 3\).

Step3: Calculate the period

Substitute \(B = 3\) into the period formula: \(T=\frac{360^{\circ}}{3}\).

$$T = 120^{\circ}$$

Answer:

120 degrees