Question

find m∠krl. m∠krl = \boxed{}

Explanation:

Step1: Identify right angle

Line \( KP \) is perpendicular to \( HM \), so \( \angle KRP = 90^\circ \).

Step2: Analyze angle sum

\( \angle KRL + \angle LRQ + \angle QRP = 90^\circ \)? No, wait, \( \angle KRL + \angle LRQ = 90^\circ \)? Wait, actually, \( \angle HRQ = 56^\circ \), and \( \angle KRL \) and \( \angle LRQ \) and \( \angle HRQ \)? Wait, no, \( KP \perp HM \), so \( \angle KRH = 90^\circ \). Wait, \( \angle KRL + \angle LRQ + \angle QRH = 90^\circ \)? No, \( \angle QRH = 56^\circ \), and \( \angle KRL \) and \( \angle LRQ \) are complementary to \( 56^\circ \)? Wait, no, \( \angle KRL + 56^\circ = 90^\circ \) because \( KP \) is perpendicular to \( HM \), so \( \angle KRP = 90^\circ \), and \( \angle LRQ \) is vertical to \( \angle HRQ \)? Wait, no, \( \angle KRL + \angle LRQ = 90^\circ \), and \( \angle LRQ = \angle HRQ = 56^\circ \) (vertical angles). So \( \angle KRL = 90^\circ - 56^\circ = 34^\circ \).
So \( m\angle KRL = 34 \).

Answer:

34