QUESTION IMAGE
Question
find ∠jmk, if the measure of ∠jml is 113°. ∠jmk =
Step1: Set up an equation
Since $\angle JML=\angle JMK+\angle KML$, we have $113=(10z + 107)+(7z + 74)$.
Step2: Combine like - terms
$113 = 10z+7z + 107+74$, which simplifies to $113=17z + 181$.
Step3: Solve for z
Subtract 181 from both sides: $113 - 181=17z$, so $- 68 = 17z$. Then divide both sides by 17: $z=-4$.
Step4: Find $\angle JMK$
Substitute $z = - 4$ into the expression for $\angle JMK$ which is $10z + 107$. So $\angle JMK=10\times(-4)+107$.
$\angle JMK=-40 + 107=67^{\circ}$.
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$67^{\circ}$