Question

find ij.
write your answer as an integer or as a decimal rounded to the nearest tenth.
ij =
submit

Explanation:

Step1: Use cosine function

In right - triangle \(KIJ\), \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). Here, \(\theta = 26^{\circ}\), the hypotenuse \(KJ = 9\), and we want to find \(IJ\). But wait, we should use \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\) (since \(IJ\) is opposite to \(\angle K\)). So \(\sin26^{\circ}=\frac{IJ}{KJ}\).

Step2: Substitute values

Since \(KJ = 9\), then \(IJ=KJ\times\sin26^{\circ}\). We know that \(\sin26^{\circ}\approx0.4384\). So \(IJ = 9\times0.4384\).

Step3: Calculate

\(IJ=9\times0.4384 = 3.9456\approx3.9\)

Answer:

\(3.9\)