find the first six terms of the sequence, starting with $n = 1$.
\a_n = 3 + (-1)^n \text{ for } n \ge 1\
$a_1 =$
$a_2 =$
$a_3 =$
$a_4 =$
$a_5 =$
$a_6 =$

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{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [], "new_concepts": [ "Sequence Terms", "Alternating Sequences" ], "current_concepts": [ "Sequence Terms", "Alternating Sequences" ] } ## Calculate the terms for odd indices $$ \begin{aligned} a_1 &= 3 + (-1)^1 = 3 - 1 = 2 \ a_3 &= 3 + (-1)^3 = 3 - 1 = 2 \ a_5 &= 3 + (-1)^5 = 3 - 1 = 2 \end{aligned} $$ ## Calculate the terms for even indices $$ \begin{aligned} a_2 &= 3 + (-1)^2 = 3 + 1 = 4 \ a_4 &= 3 + (-1)^4 = 3 + 1 = 4 \ a_6 &= 3 + (-1)^6 = 3 + 1 = 4 \end{aligned} $$ Find the first six terms of the sequence, starting with $n = 1$. $a_n = 3 + (-1)^n$ for $n \ge 1$ $a_1 =$ 2 $a_2 =$ 4 $a_3 =$ 2 $a_4 =$ 4 $a_5 =$ 2 $a_6 =$ 4 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Sequence Terms" ] }

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Explanation:

Calculate the terms for odd indices

Calculate the terms for even indices

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