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find the distance between the points (8, -10) and (3, 2). round decimal…

Question

find the distance between the points (8, -10) and (3, 2).
round decimals to the nearest tenth.
14.0
15.0
12.0
13.0

Explanation:

Step1: Identify the coordinates

Let \((x_1,y_1)=(8,-10)\) and \((x_2,y_2)=(3,2)\)

Step2: Use the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

Substitute the values: \(d=\sqrt{(3 - 8)^2+(2-(-10))^2}\)

Step3: Simplify the expression inside the square root

First, \((3 - 8)=-5\) and \((2 + 10)=12\). Then \((-5)^2=25\) and \(12^2 = 144\). So \(d=\sqrt{25 + 144}\)

Step4: Calculate the sum and the square root

\(25+144 = 169\), and \(\sqrt{169}=13\)

Answer:

13.0