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find the distance between each pair of points. round your answer to the…

Question

find the distance between each pair of points. round your answer to the nearest tenth, if necessary.

  1. (7, 6), (0, 2)
  2. (4, 2), (-6, -6)
  3. (-6, 1), (-3, 1)
  4. (-3, 6), (2, 1)

11)
12)
13)
14)

Explanation:

Identify the distance formula

To find the distance \(d\) between any two points \((x_1, y_1)\) and \((x_2, y_2)\) on a coordinate plane, we use the Distance Formula:

$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

We will apply this formula to each pair of points, rounding to the nearest tenth when necessary.

Calculate distances for coordinate pairs (7 to 10)

  • Question 7: Points \((7, 6)\) and \((0, 2)\)
$$d = \sqrt{(0 - 7)^2 + (2 - 6)^2} = \sqrt{(-7)^2 + (-4)^2} = \sqrt{49 + 16} = \sqrt{65} \approx 8.1$$
  • Question 8: Points \((4, 2)\) and \((-6, -6)\)
$$d = \sqrt{(-6 - 4)^2 + (-6 - 2)^2} = \sqrt{(-10)^2 + (-8)^2} = \sqrt{100 + 64} = \sqrt{164} \approx 12.8$$
  • Question 9: Points \((-6, 1)\) and \((-3, 1)\)

Since the \(y\)-coordinates are equal, the distance is the horizontal difference:

$$d = |-3 - (-6)| = |-3 + 6| = 3$$
  • Question 10: Points \((-3, 6)\) and \((2, 1)\)
$$d = \sqrt{(2 - (-3))^2 + (1 - 6)^2} = \sqrt{(5)^2 + (-5)^2} = \sqrt{25 + 25} = \sqrt{50} \approx 7.1$$

Identify coordinates from graphs (11 to 14)

We read the endpoints of each segment from the grid:

  • Question 11: Endpoints are \((-1, 4)\) and \((3, -1)\)
  • Question 12: Endpoints are \((-4, 2)\) and \((5, -3)\)
  • Question 13: Endpoints are \((0, -2)\) and \((1, -4)\)
  • Question 14: Endpoints are \((-4, -3)\) and \((1, 0)\)

Calculate distances for graphed segments (11 to 14)

  • Question 11: Points \((-1, 4)\) and \((3, -1)\)
$$d = \sqrt{(3 - (-1))^2 + (-1 - 4)^2} = \sqrt{4^2 + (-5)^2} = \sqrt{16 + 25} = \sqrt{41} \approx 6.4$$
  • Question 12: Points \((-4, 2)\) and \((5, -3)\)
$$d = \sqrt{(5 - (-4))^2 + (-3 - 2)^2} = \sqrt{9^2 + (-5)^2} = \sqrt{81 + 25} = \sqrt{106} \approx 10.3$$
  • Question 13: Points \((0, -2)\) and \((1, -4)\)
$$d = \sqrt{(1 - 0)^2 + (-4 - (-2))^2} = \sqrt{1^2 + (-2)^2} = \sqrt{1 + 4} = \sqrt{5} \approx 2.2$$
  • Question 14: Points \((-4, -3)\) and \((1, 0)\)
$$d = \sqrt{(1 - (-4))^2 + (0 - (-3))^2} = \sqrt{5^2 + 3^2} = \sqrt{25 + 9} = \sqrt{34} \approx 5.8$$

Answer:

Question 7

\(8.1\)

Question 8

\(12.8\)

Question 9

\(3\)

Question 10

\(7.1\)

Question 11

\(6.4\)

Question 12

\(10.3\)

Question 13

\(2.2\)

Question 14

\(5.8\)