Question

find the discriminant.
6q² + 2 = 0
what type of solutions does the equation have?
one real solution
two real solutions
two complex (non - real) solutions

Explanation:

Step1: Identify coefficients

For the quadratic equation $6q^{2}+0q + 2=0$, $a = 6$, $b = 0$, $c = 2$.

Step2: Calculate discriminant

The discriminant formula is $\Delta=b^{2}-4ac$. Substitute the values: $\Delta=(0)^{2}-4\times6\times2=0 - 48=- 48$.

Step3: Determine solution type

Since $\Delta=-48<0$, the quadratic equation has two complex (non - real) solutions.

Answer:

Discriminant: $-48$
Solution type: two complex (non - real) solutions