Question

find the coordinates for the vertex of the following quadratic function.
$f(x) = -\frac{12}{13}(x + 4)^2 + 4$

Explanation:

Step1: Recall vertex form of quadratic

The vertex form of a quadratic function is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex.

Step2: Compare with given function

Given \( f(x)=-\frac{12}{13}(x + 4)^2+4 \), rewrite \( (x + 4) \) as \( (x - (- 4)) \). So comparing with \( a(x - h)^2 + k \), we have \( h=-4 \) and \( k = 4 \).

Answer:

The vertex coordinates are \((-4, 4)\)