Question

find the area of the figure. (sides meet at right angles.)

Explanation:

Step1: Calculate the area of the upper rectangle

The length of the upper rectangle is \(2 + 5+ 2=9\) inches and the width is \(2\) inches. Using the formula for the area of a rectangle \(A = l\times w\), we have \(A_1=9\times2 = 18\) square inches.

Step2: Calculate the area of the lower square

The side - length of the lower square is \(5\) inches. Using the formula for the area of a square \(A = s\times s\) (where \(s\) is the side - length), we have \(A_2 = 5\times5=25\) square inches.

Step3: Sum the two areas

The total area \(A=A_1 + A_2\). So \(A=18 + 25=43\) square inches.

Answer:

\(43\) square inches