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find the area of each trapezoid. 1) 8 in 7 in 6 in area =

Question

find the area of each trapezoid.

1)

8 in
7 in
6 in

area =

Explanation:

Identify the given dimensions

We are given a right trapezoid with:

  • Top base \(b_1 = 8\text{ in}\)
  • Bottom base \(b_2 = 6\text{ in}\)
  • Height \(h = 7\text{ in}\)

Recall the area formula

The formula for the area of a trapezoid is:

$$A = \frac{1}{2} \cdot (b_1 + b_2) \cdot h$$

Substitute the values

Substitute the given dimensions into the formula:

$$A = \frac{1}{2} \cdot (8 + 6) \cdot 7$$

Simplify the expression

Add the bases first, then multiply:

$$A = \frac{1}{2} \cdot 14 \cdot 7$$
$$A = 7 \cdot 7 = 49$$

The area is \(49\text{ in}^2\).

Answer:

Area = <blank>\(49\text{ in}^2\)</blank>