Question

find the area.
area of \\( \triangle = ? \mathrm { in } ^ { 2 } \\)
area of \\( \square = \square \mathrm { in } ^ { 2 } \\)
remember:
\\( a _ { \triangle } = \frac { 1 } { 2 } b h \\)
area of figure \\( = \square \mathrm { in } ^ { 2 } \\)

Explanation:

Step1: Calculate the area of the triangle

Use the formula $A_{\triangle}=\frac{1}{2}bh$. Here, $b = 16$ in and $h = 5$ in.
$$A_{\triangle}=\frac{1}{2}\times16\times5 = 8\times5=40$$

Step2: Calculate the area of the rectangle

Use the formula $A_{\square}=l\times w$. Here, $l = 16$ in and $w = 9$ in.
$$A_{\square}=16\times9 = 144$$

Step3: Calculate the area of the figure

Add the area of the triangle and the area of the rectangle.
$$A = A_{\triangle}+A_{\square}=40 + 144=184$$

Answer:

Area of $\triangle = 40$ in$^2$
Area of $\square = 144$ in$^2$
Area of Figure $= 184$ in$^2$