Question

find g:
8(g + 1) = 32
a g = 4
b g = 31
c g = 3

Explanation:

Step1: Divide both sides by 8

To isolate the term with \( g \), divide both sides of the equation \( 8(g + 1)=32 \) by 8.
\( \frac{8(g + 1)}{8}=\frac{32}{8} \)
Simplifying, we get \( g + 1 = 4 \).

Step2: Subtract 1 from both sides

To solve for \( g \), subtract 1 from both sides of the equation \( g + 1 = 4 \).
\( g + 1 - 1 = 4 - 1 \)
Simplifying, we get \( g = 3 \). Wait, no—wait, let's check again. Wait, \( 32\div8 = 4 \), so \( g + 1 = 4 \), then \( g = 4 - 1 = 3 \)? Wait, but option C is \( g = 3 \). Wait, maybe I made a mistake earlier. Wait, let's re - solve:

Starting over: \( 8(g + 1)=32 \)

Divide both sides by 8: \( g + 1=\frac{32}{8}=4 \)

Subtract 1 from both sides: \( g = 4 - 1 = 3 \). So the correct answer is C. \( g = 3 \). Wait, but the initial selected option was A, but that's incorrect. Let's verify by plugging back in.

For option A: \( g = 4 \), then \( 8(4 + 1)=8\times5 = 40
eq32 \).

For option C: \( g = 3 \), then \( 8(3 + 1)=8\times4 = 32 \), which matches the right - hand side. So the correct answer is C.

Answer:

C. \( g = 3 \)