Question

find $h(-1)$.
$f(x)$
$h(x) = 3x^2 - 4x - 2$

$x$	$g(x)$
$-6$	$10$
$10$	$2$
$2$	$2$
$-4$	$0$

answer

Explanation:

Step1: Substitute \( x = -1 \) into \( h(x) \)

We have the function \( h(x) = 3x^2 - 4x - 2 \). To find \( h(-1) \), we substitute \( x = -1 \) into the function. So we get \( h(-1)=3(-1)^2 - 4(-1)-2 \).

Step2: Calculate each term

First, calculate \( (-1)^2 = 1 \), so \( 3(-1)^2 = 3\times1 = 3 \). Then, \( -4(-1)=4 \). Now substitute these back into the expression: \( h(-1)=3 + 4 - 2 \).

Step3: Simplify the expression

Now, perform the arithmetic operations: \( 3 + 4 = 7 \), and then \( 7 - 2 = 5 \).

Answer:

\( 5 \)