Question

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table.
some ionic compounds
cation \t anion \t empirical formula \t name of compound
na⁺ \t no₂⁻ \t \t
k⁺ \t bro₃⁻ \t \t
na⁺ \t io₃⁻ \t \t

Explanation:

First Row (Cation: $\boldsymbol{\ce{Na+}}$, Anion: $\boldsymbol{\ce{NO2-}}$)

Step1: Determine the ratio of ions

Since $\ce{Na+}$ has a charge of $+1$ and $\ce{NO2-}$ has a charge of $-1$, the ratio of cation to anion is $1:1$ to balance the charges.

Step2: Write the empirical formula

Using the ratio, the empirical formula is $\ce{NaNO2}$.

Step3: Name the compound

The cation is sodium ($\ce{Na+}$) and the anion is nitrite ($\ce{NO2-}$), so the name is sodium nitrite.

Second Row (Cation: $\boldsymbol{\ce{K+}}$, Anion: $\boldsymbol{\ce{BrO3-}}$)

Step1: Determine the ratio of ions

$\ce{K+}$ has a charge of $+1$ and $\ce{BrO3-}$ has a charge of $-1$, so the ratio of cation to anion is $1:1$.

Step2: Write the empirical formula

The empirical formula is $\ce{KBrO3}$.

Step3: Name the compound

The cation is potassium ($\ce{K+}$) and the anion is bromate ($\ce{BrO3-}$), so the name is potassium bromate.

Third Row (Cation: $\boldsymbol{\ce{Na+}}$, Anion: $\boldsymbol{\ce{IO3-}}$)

Step1: Determine the ratio of ions

$\ce{Na+}$ has a charge of $+1$ and $\ce{IO3-}$ has a charge of $-1$, so the ratio of cation to anion is $1:1$.

Step2: Write the empirical formula

The empirical formula is $\ce{NaIO3}$.

Step3: Name the compound

The cation is sodium ($\ce{Na+}$) and the anion is iodate ($\ce{IO3-}$), so the name is sodium iodate.

Answer:

Cation	Anion	Empirical Formula	Name of Compound
$\ce{K+}$	$\ce{BrO3-}$	$\ce{KBrO3}$	Potassium Bromate
$\ce{Na+}$	$\ce{IO3-}$	$\ce{NaIO3}$	Sodium Iodate